Hint 1:
a/b is the ratio of a to b . That is a:b
Hint 2:
When two ratios are equal, they are said to be in proportion.
Example:
If a:b = c:d, then a,b,c & d are proportion.
Hint 3:
Cross  product rule in proportion:
Product of extremes = Product of means.
Example:
Let us consider the proportion a:b = c:d
Extremes = a & d, means = b & c
Then, as per the cross product rule, we have
Hint 4:
Inverse ratios:
b:a is the inverse ratio of a:b and vice versa.
That is, a:b & b:a are the two ratios inverse to each other.
Hint 5:
Verification of inverse ratios:
If two ratios are inverse to each other, then their product must be 1.
That is, a:b & b:a are two ratios inverse to each other.
Then, (a:b)X(c:d) = (a/b)X(c/b) = ad/bc = 1
Hint 6:
If the ratio of two quantities is given and we want to get the original quantities, we have to multiply both the terms of the ratio by some constant, say “x”.
Example:
The ratio of earnings of two persons is 3:4.
Then,
the earning of the first person = 3x
the earning of the second person = 4x
Hint 7:
If we want compare any two ratios, first we have to express the given ratios as fractions.
Then, we have to make them to be like fractions.
That is, we have to convert the fractions to have same denominators.
Example:
Compare: 3:5 and 4:7.
First, let us write the ratios 3:5 and 4:7 as fractions.
That is 3/5 and 4/7.
The above two fractions do not have the same denominators. Let us make them to be same.
For that, we have to find L.C.M of the denominators (5,7).
That is, 5X7 = 35. We have to make each denominator as 35.
Then the fractions will be 21/35 and 20/35.
Now compare the numerators 21 and 20.
21 is greater.
So the first fraction is greater.
Hence the first ratio 3:5 is greater than 4:7.
Hint 8:
If two ratios P:Q and Q:R are given and we want to find the ratio P:Q:R, we have to do the following steps.
First find the common tern in the given two ratios P:Q and Q:R. That is Q.
In both the ratios try to get the same value for “Q”.
After having done the above step, take the values corresponding to P, Q, R in the above ratios and form the ratio P:Q:R.
Example:
If P:Q = 2:3 and Q:R = 4:7, find the ratio P:Q:R.
In the above two ratios, we find “Q” in common.
The value corresponding to Q in the first ratio is 3 and in the second ratio is 4.
L.C.M of (3, 4) = 12.
So, if multiply the first ratio by 4 and second by 3,
we get P:Q = 8:12 and Q:R = 12:21
Now we have same value (12) for “Q” in both the ratios.
Now the values corresponding to P, Q & R are 8, 12 & 21.
Hence the ratio P:Q:R = 8:12:21
Hint 9:
If the ratio of speeds of two vehicles in the ratio a:b, then time taken ratio of the two vehicles would be b:a.
Example:
The ratio of speeds of two vehicles is 2:3. Then time taken ratio of the two vehicles to cover the same distance would be 3:2.
Hint 10:
If the ratio of speeds of two vehicles in the ratio a:b, then the distance covered ratio in the same amount of time  would also be a:b.
Example:
The ratio of speeds of two vehicles is 2:3. Each vehicle is given one hour time. Then, the distance covered by the two vehicles would be in the ratio 2:3.
Hint 11:
If A is twice as good as B, then the work completed ratio of A and B in the same amount of time would be 2:1.
Example:
A is twice as good as B and each given 1 hour time.  If A completes 2 unit of work in 1 hour, then B will complete 1 unit of work in one hour.
Hint 12:
If A is twice as good as B, then the tame taken ratio of A and B to do the same work would be 1:2.
Example:
A is twice as good as B and each given the same amount of work to complete. If A takes 1 hour to complete the work, then B will take 2 hours to complete the same work.
Hint 13:
If “m” kg of one kind costing \$a per kg is mixed with “n” kg of another kind costing \$b per kg, then the price of the mixture would be \$ (ma+nb)/(m+n) per kg.
Hint 14:
If one quantity increased or decreases in the ratio a:b,
then the new quantity is = “b” of the original quantity/a
More clearly, new quantity = (“b” X original quantity) / a
Example:
David weighs 56 kg. If he reduces his weight in the ratio 7:6, find his new weight.
New weight = (6 X 56) / 7 = 48 kg.
Hence, David’s new weight = 48 kg.